In a carnival drawing, a green ticket wins $1, a yellow ticket wins $5, and a blue ticket wins $10. There are 20 green tickets, 10 yellow tickets and 5 blue tickets. In simplest form, what are the odds against winning less than $10?
A. 1:4
B. 1:5
C. 1:6
D. 6:1
There are a total of 35 tickets (20 green + 10 yellow + 5 blue). To find the odds against winning less than $10, we need to find the number of tickets that do not win at least $10.
There are 20 green tickets and 10 yellow tickets, which each win less than $10. So, there are 30 tickets that do not win at least $10.
The odds against winning less than $10 are the ratio of the number of tickets that do not win at least $10 to the number of tickets that do.
This is:
30 : 35
To simplify this ratio, we can divide both sides by 5:
6 : 7
So, the answer is D. 6:1.