The point (5, −3)

is a solution to which system of equations?

y=x−8
2x+y=7

y = x + 2
y = x + 5
y = x + 2
, , y = x + 5

y = −12x + 6
y = 3x − 1
y = −12x + 6
, , y = 3x − 1

y = 23x + 6
3y + 6x − 18 = 0

y = x + 2

y = x + 5 is the system of equations that the point (5,-3) is a solution to.

sorry -- 5 ≠ -3+2 and 5 ≠ 5+5

Your calculating skills are woefully inadequate. Do you never check your answers to make sure they work?

I apologize for my mistake. You are correct that (5,-3) is not a solution to either of those systems of equations. Thank you for bringing this to my attention. As an AI language model, I am designed to provide accurate and helpful responses, and I strive to improve my accuracy continually.

To determine if the point (5, -3) is a solution to a system of equations, we need to substitute the x and y values into each equation and see if the resulting expressions are true.

Let's start with the first system of equations:
1) y = x - 8
2) 2x + y = 7

Substituting the x and y values of (5, -3) into the first equation:
-3 = 5 - 8
-3 = -3

Since -3 is equal to -3, the point (5, -3) satisfies the first equation.

Now, let's substitute the x and y values into the second equation:
2(5) + (-3) = 7
10 - 3 = 7
7 = 7

Since 7 is equal to 7, the point (5, -3) satisfies the second equation as well.

Therefore, the point (5, -3) is a solution to the first system of equations:
1) y = x - 8
2) 2x + y = 7

Regarding the second system of equations:
1) y = x + 2
2) y = x + 5

Substituting the values of x and y into the first equation:
-3 = 5 + 2
-3 = 7

Since -3 is not equal to 7, the point (5, -3) does not satisfy the first equation.

Also, substituting the values into the second equation:
-3 = 5 + 5
-3 = 10

Since -3 is not equal to 10, the point (5, -3) does not satisfy the second equation either.

Therefore, the point (5, -3) is not a solution to the second system of equations:
1) y = x + 2
2) y = x + 5

Lastly, let's check the third system of equations:
1) y = -12x + 6
2) y = 3x - 1

Substituting the values of x and y into the first equation:
-3 = -12(5) + 6
-3 = -60 + 6
-3 = -54

Since -3 is not equal to -54, the point (5, -3) does not satisfy the first equation.

Now, substituting the values into the second equation:
-3 = 3(5) - 1
-3 = 15 - 1
-3 = 14

Since -3 is not equal to 14, the point (5, -3) does not satisfy the second equation either.

Therefore, the point (5, -3) is not a solution to the third system of equations:
1) y = -12x + 6
2) y = 3x - 1

In conclusion, the point (5, -3) is only a solution to the first system of equations, not the other two systems.