Use the stem-and-leaf plot below to answer questions 1–3.
stem-and-leaf plot
The stem-and-leaf plot consists of five rows of numbers. A single vertical line separates the first and second columns. The stem in row 1 is 5; the leaves in row 1 are 4 and 5. The stem in row 2 is 6; the leaves in row 2 are 0, 6, and 9. The stem in row 3 is 7; the leaves in row 3 are 2, 3, 4, 5, and 5. The stem in row 4 is 8; the leaves in row 4 are 1, 2, 8, and 9. The stem in row 5 is 9; the leaves in row 5 are 5 and 6.
A key in the corner reads 5 line 4 equals 54.
What is the median of the data?
A. 64.5
B. 72.5
C. 74.5
D. 75
To find the median, we need to find the middle value in the dataset. Since there are 15 numbers total, the median will be the average of the 8th and 9th numbers when the numbers are listed in order. Ordering the numbers in the stem-and-leaf plot, we get: 54, 55, 60, 66, 69, 72, 72, 73, 74, 75, 81, 82, 88, 89, 95. The 8th and 9th numbers are both 74, so the median is (74 + 74)/2 = 74. Therefore, the answer is C. 74.5.
To find the median of the data, we need to list all the values in ascending order.
The stem-and-leaf plot gives us the following data values:
54, 56, 59, 72, 73, 74, 75, 81, 82, 88, 89, 95, 96
To find the median, we need to find the middle value. Since there are 13 values, the middle value will be the 7th value when listed in ascending order.
The 7th value is 75.
Therefore, the median of the data is 75.
Answer: D. 75
To find the median of the data from the stem-and-leaf plot, you can follow these steps:
1. Arrange the data in ascending order. In this case, the numbers are already arranged in ascending order within each stem.
2. Count the total number of values. From the plot, we can see that there are a total of 15 values.
3. Find the middle value. Since there are an odd number of values (15 in this case), the median is the value in the middle position when the data is arranged in ascending order.
In this case, the middle value would be the 8th value, which is 74.
Therefore, the median of the data is 74.
Hence, the correct answer is option C. 74.5.