What is a histogram and how do you find it
As an AI language model, I don't have any visual capabilities to find a histogram. However, I can provide you with the definition of a histogram.
A histogram is a graphical representation of a frequency distribution of a set of data. It consists of vertical bars that represent the frequency or percentage of occurrence of data within specific intervals known as classes or bins. The horizontal axis represents the range of values of the data and the vertical axis represents the frequency or percentage of observations falling within each class. Histograms can be useful for identifying patterns, trends, and outliers in the data. They are commonly used in statistics, data analysis, and other fields.
Researchers count 30 tagged zebras and 150 total zebras in an area of a game reserve. If researchers had previously tagged 80 total zebras at the game reserve, about how many total zebras live at the game reserve? Write a proportion to estimate the total population.
To solve this problem using proportion, we can use the following formula:
(tagged zebras in sample)/(total zebras in sample) = (tagged zebras in population)/(total zebras in population)
We can substitute the given values into this formula and solve for the unknown value:
(30/150) = (80/x)
Cross-multiplying 30x = 80*150
x = (80*150)/30
x = 400
Therefore, the estimated total population of zebras in the game reserve is 400.
The proportion can be written as:
(tagged zebras in sample)/(total zebras in sample) = (tagged zebras in population)/(total zebras in population)
30/150 = 80/x
where x is the total zebras in the population.
Maria has the following scores on exams in her social studies class: 86, 75, 97, 58, 94, and 58.
Find the mean, median, and mode of the scores.
Should Maria’s social studies teacher use the mean, median, or mode of the exam scores to convince Maria that she needs to study more regularly for her exams?
To find the mean of Maria's exam scores, we can add up all the scores and divide by the total number of scores:
Mean = (86+75+97+58+94+58)/6 = 77.67
To find the median of Maria's exam scores, we need to put them in order from lowest to highest:
58, 58, 75, 86, 94, 97
Since there are an even number of scores, we need to take the average of the two middle scores to find the median:
Median = (75+86)/2 = 80.5
To find the mode of Maria's exam scores, we need to find the score that appears most often:
Mode = 58
Based on these results, Maria's social studies teacher should use the mean score to convince her to study more regularly. The mean score gives a good overall representation of Maria's performance, and it shows that she needs to improve in order to raise her average score. The median and mode scores are less useful in this context, as they only reflect specific aspects of Maria's score distribution (in this case, a few low scores).
The stem-and-leaf plot shows the heights in centimeters of Teddy Bear sunflowers grown in two different types of soil.
Soil A Soil B
5 9
5 2 1 1 6 3 9
5 1 0 7 0 2 3 6 7 8
2 1 8 3
0 9
Key: 9|6 means 69 Key: 5|8 means 58
Calculate the mean of each data set.
Calculate the mean absolute deviation (MAD) of each data set.
Which set is more variable? How do you know?
To calculate the mean of each data set, we can use the stem-and-leaf plot to find the individual values and then calculate the mean:
For Soil A:
21+51+51+52+52+52+60+70+81+90 = 608
Mean = 608/11 = 55.27
For Soil B:
30+32+33+36+37+38+39+60+63+69+70 = 507
Mean = 507/11 = 46.09
To calculate the mean absolute deviation of each data set, we need to first calculate the deviation of each value from the mean. Then, we can take the absolute value of each deviation, sum them up, and divide by the number of values:
For Soil A:
|21-55.27| = 34.27
|51-55.27| = 4.27
|51-55.27| = 4.27
|52-55.27| = 3.27
|52-55.27| = 3.27
|52-55.27| = 3.27
|60-55.27| = 4.73
|70-55.27| = 14.73
|81-55.27| = 25.73
|90-55.27| = 34.73
MAD = (34.27+4.27+4.27+3.27+3.27+3.27+4.73+14.73+25.73+34.73)/11 = 9.39
For Soil B:
|30-46.09| = 16.09
|32-46.09| = 14.09
|33-46.09| = 13.09
|36-46.09| = 10.09
|37-46.09| = 9.09
|38-46.09| = 8.09
|39-46.09| = 7.09
|60-46.09| = 13.91
|63-46.09| = 16.91
|69-46.09| = 22.91
|70-46.09| = 23.91
MAD = (16.09+14.09+13.09+10.09+9.09+8.09+7.09+13.91+16.91+22.91+23.91)/11 = 13.24
Based on the MAD values, Soil B has a larger variability compared to Soil A. Soil B has a MAD of 13.24, which means that the data points are more spread out compared to Soil A, which has a MAD of 9.39.