There are 2 light bulbs in a circuit,wired in parallel. Athird light bulb is added again in parallel.What is the effect on total resistance of adding this third light bulb? answer c. Total resistance decreases?
As the light bulbs are wired in parallel, the total resistance of the circuit decreases when a third light bulb is added. This is because each additional bulb provides an additional path for the current to flow, reducing the overall resistance of the circuit. Therefore, answer c, i.e., "Total resistance decreases" is correct.
Answer -Total resistance decreases.
That is correct. Adding a third light bulb in parallel reduces the total resistance of the circuit.
To determine the effect of adding a third light bulb in parallel on the total resistance of the circuit, we need to understand how resistors in parallel behave.
When resistors are connected in parallel, the total resistance decreases. This is because the current can flow through multiple paths, dividing itself among the resistors. As a result, the addition of the third light bulb in parallel will decrease the total resistance of the circuit.
To calculate the total resistance when resistors are in parallel, you can use the following formula:
1/total resistance = 1/resistor1 + 1/resistor2 + 1/resistor3 + ...
In this case, since we have only two light bulbs connected in parallel initially, the formula would be:
1/total resistance = 1/resistor1 + 1/resistor2
Now, if we add the third light bulb in parallel, the formula would become:
1/total resistance = 1/resistor1 + 1/resistor2 + 1/resistor3
Therefore, as the number of resistors in parallel increases, the total resistance of the circuit decreases.