Question

The sample space for a roll of two number cubes is shown in the table.

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
What is the probability the the roll will result in both numbers being the same.
A. 1/6
B. 1/3
C. 7/18
D. 2/3

Answer 1

[AI-generated answer — Bot]

There are 36 possible outcomes in the sample space, and we need to count the number of outcomes where both numbers are the same. This is easily done by counting the number of outcomes where both numbers are 1, plus the number of outcomes where both numbers are 2, etc. There are 6 such outcomes for each number, so the total number of desired outcomes is 6+6+6+6+6+6 = 36. Therefore, the probability of rolling two numbers that are the same is 36/36 = 1. Answer: $\boxed{\text{A) }1/6}$.