How much more kinetic energy does a 6-kilogram bowling ball have when it’s rolling at 16 mph 7.1 meters per second than when it is rolling at 14mph 6.2 meters per second
To solve this problem, we need to use the formula for kinetic energy:
KE = 0.5 * m * v^2
where KE is the kinetic energy, m is the mass, and v is the velocity.
First, let's find the kinetic energy of the bowling ball when it's rolling at 16 mph:
KE1 = 0.5 * 6 kg * (7.1 m/s)^2
KE1 = 151.41 J
Now, let's find the kinetic energy of the bowling ball when it's rolling at 14 mph:
KE2 = 0.5 * 6 kg * (6.2 m/s)^2
KE2 = 113.04 J
The difference in kinetic energy is:
ΔKE = KE1 - KE2
ΔKE = 151.41 J - 113.04 J
ΔKE = 38.37 J
Therefore, the bowling ball has 38.37 more joules of kinetic energy when it's rolling at 16 mph compared to when it's rolling at 14 mph.
To calculate the difference in kinetic energy, we need to use the formula for kinetic energy:
KE = 1/2 * m * v^2
where KE is the kinetic energy, m is the mass, and v is the velocity.
First, let's calculate the kinetic energy of the bowling ball rolling at 16 mph (7.1 m/s):
KE1 = 1/2 * 6 kg * (7.1 m/s)^2
KE1 = 1/2 * 6 kg * 50.41 m^2/s^2
KE1 = 151.23 joules
Next, let's calculate the kinetic energy of the bowling ball rolling at 14 mph (6.2 m/s):
KE2 = 1/2 * 6 kg * (6.2 m/s)^2
KE2 = 1/2 * 6 kg * 38.44 m^2/s^2
KE2 = 115.32 joules
Finally, we can find the difference in kinetic energy:
Difference = KE1 - KE2
Difference = 151.23 joules - 115.32 joules
Difference = 35.91 joules
Therefore, the bowling ball has 35.91 joules more kinetic energy when it is rolling at 16 mph (7.1 m/s) compared to when it is rolling at 14 mph (6.2 m/s).
To calculate the kinetic energy of the bowling ball at two different speeds, we need to use the formula for kinetic energy, which is given by:
KE = (1/2) * m * v^2
Where:
KE represents the kinetic energy
m represents the mass of the bowling ball
v represents the velocity of the bowling ball
Let's first calculate the kinetic energy of the bowling ball at 16 mph or 7.1 meters per second:
Mass of the bowling ball, m = 6 kg
Velocity of the bowling ball, v = 7.1 m/s
So, the kinetic energy at this speed would be:
KE1 = (1/2) * 6 kg * (7.1 m/s)^2
Next, let's calculate the kinetic energy of the bowling ball at 14 mph or 6.2 meters per second:
Mass of the bowling ball, m = 6 kg
Velocity of the bowling ball, v = 6.2 m/s
So, the kinetic energy at this speed would be:
KE2 = (1/2) * 6 kg * (6.2 m/s)^2
Finally, we can find the difference in kinetic energy:
Difference in kinetic energy = KE1 - KE2
Let's plug in the values to calculate the difference.