One side of a rectangle equals x + 10, and the other is 2x + 3. What is the value of x if the perimeter equals 50?
To find the perimeter of a rectangle, you add up the lengths of all four sides. So if one side is x + 10 and the other is 2x + 3, then the perimeter would be:
P = 2(x + 10) + 2(2x + 3)
P = 2x + 20 + 4x + 6
P = 6x + 26
Now we can set this equal to 50 (as the problem states) and solve for x:
6x + 26 = 50
6x = 24
x = 4
Therefore, the value of x is 4.
To find the value of x, we'll use the formula for the perimeter of a rectangle, which is P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.
Given that one side of the rectangle equals x + 10, and the other side equals 2x + 3, we can set up the equation as follows:
P = 2(x + 10) + 2(2x + 3)
Now, let's simplify the equation:
50 = 2x + 20 + 4x + 6
Combine like terms:
50 = 6x + 26
Subtract 26 from both sides:
24 = 6x
Divide both sides by 6:
4 = x
Therefore, the value of x is 4.
To find the value of x, we need to set up an equation based on the given information.
The perimeter of a rectangle is the sum of all its sides. In this case, the perimeter is equal to 50.
The given information states that one side of the rectangle is x + 10 and the other side is 2x + 3.
So, the equation for the perimeter is:
Perimeter = 2 * (x + 10) + 2 * (2x + 3)
Now, we can simplify this equation and solve for x:
50 = 2x + 20 + 4x + 6
Combining like terms, we have:
50 = 6x + 26
Subtracting 26 from both sides, we get:
24 = 6x
Finally, dividing both sides by 6, we find:
x = 4
Therefore, the value of x is 4.