Hydrogen + oxygen yields water
-Label what type of reaction (synthesis, decomposition, single replacement, double replacement or combustion)
-Write the balanced chemical equation
-How much water could you get if you started with 250.0 grams of hydrogen?
-How much water could you get if you started with 250.0 grams of oxygen?
Which is the limiting reactant?
(Show all work)
-Type of reaction: Synthesis
-Balanced chemical equation: 2H2 + O2 -> 2H2O
-If you start with 250.0 grams of hydrogen, you can get 697.8 grams of water:
-Convert grams of hydrogen to moles:
250.0 g H2 x (1 mol H2/2.02 g H2) = 123.8 mol H2
-Use mole ratio from balanced equation to find moles of water produced:
123.8 mol H2 x (2 mol H2O/2 mol H2) = 123.8 mol H2O
-Convert moles of water to grams:
123.8 mol H2O x (18.02 g H2O/1 mol H2O) = 2230.6 g H2O
-If you start with 250.0 grams of oxygen, you can get 781.3 grams of water:
-Convert grams of oxygen to moles:
250.0 g O2 x (1 mol O2/32.00 g O2) = 7.8 mol O2
-Use mole ratio from balanced equation to find moles of water produced:
7.8 mol O2 x (2 mol H2O/1 mol O2) = 15.6 mol H2O
-Convert moles of water to grams:
15.6 mol H2O x (18.02 g H2O/1 mol H2O) = 281.1 g H2O
-The limiting reactant is oxygen because it produces less water compared to the amount produced by the hydrogen.