An insect living on a plant doubles its number every 5 days until they are 348 insects in living on the plants some insects then move to another plant the formula p is equal to 3 * 2d gives the number of insect on the plant d is the number of days calculate the number of inserts on the plant after 6 days
Let's first find the number of days it takes for the insects to reach 348.
The formula is P = 3 * 2^d, where P is the number of insects and d is the number of days.
We are given P = 348.
348 = 3 * 2^d
To get d, we need to solve for d in the equation. First, we can divide both sides of the equation by 3:
348 / 3 = (3 * 2^d) / 3
116 = 2^d
Now we need to find the value of d that satisfies the equation. To do this, we take the logarithm base 2 of both sides of the equation:
log2(116) = log2(2^d)
log2(116) = d
Using a calculator, we find:
d ≈ 6.54
Since the insects double every 5 days, it only takes about 6.54 days to reach 348 insects. The problem asks for the number of insects on the plant after 6 days.
The insects double on the 5th day, so we know that there are 348 / 2 = 174 insects after 5 days. Since the insects double every 5 days, there is no more doubling on the 6th day, and the number of insects on the plant after 6 days remains 174.