how many moles are in 30.0g of ethanol (CH3CH2OH)?
element - molar mass
carbon: 12.01
hydrogen: 1.01
oxygen: 16.00
show work
The molar mass of ethanol (CH3CH2OH) can be calculated as:
12.01 + 3(1.01) + 2(12.01) + 1(16.00) = 46.07 g/mol
To find the number of moles present in 30.0g of ethanol, we can use the formula:
moles = mass/molar mass
moles = 30.0g/46.07 g/mol
moles = 0.651 mol
Therefore, there are 0.651 moles of ethanol present in 30.0g of ethanol.
e
I'm sorry, I don't understand what you mean by "e". Please provide more context or a specific question.
To find the number of moles in 30.0g of ethanol (CH3CH2OH), you can follow these steps:
Step 1: Determine the molar mass of ethanol (CH3CH2OH).
To calculate the molar mass, you need to multiply the atomic mass of each element by its subscript in the chemical formula and then add them together.
Molar mass of carbon (C): 12.01 g/mol
Molar mass of hydrogen (H): 1.01 g/mol
Molar mass of oxygen (O): 16.00 g/mol
Now, calculate the molar mass of ethanol:
(2 × C) + (6 × H) + O + H
= (2 × 12.01 g/mol) + (6 × 1.01 g/mol) + (16.00 g/mol) + (1.01 g/mol)
= 24.02 g/mol + 6.06 g/mol + 16.00 g/mol + 1.01 g/mol
= 47.09 g/mol
Therefore, the molar mass of ethanol (CH3CH2OH) is 47.09 g/mol.
Step 2: Use the molar mass to calculate the number of moles.
To calculate the number of moles, you can use the formula:
moles = mass (in grams) / molar mass
In this case, the mass is 30.0g, and the molar mass is 47.09 g/mol.
moles = 30.0g / 47.09 g/mol
= 0.637 moles (rounded to three decimal places)
Therefore, there are approximately 0.637 moles in 30.0g of ethanol (CH3CH2OH).