15. Chris has a jar with nickels and quarters in it. There are 95 coins in the jar and the coins total $12.95. How many of each coin is there?
Let x be the number of nickels and y be the number of quarters.
We can create a system of two equations based on the given information:
x + y = 95 (equation 1: the total number of coins is 95)
0.05x + 0.25y = 12.95 (equation 2: the total value of the coins is $12.95)
To solve for x and y, we can use elimination or substitution.
Using elimination, we can multiply equation 1 by -0.05 and add it to equation 2:
-0.05x - 0.05y = -4.75 (equation 1 multiplied by -0.05)
0.05x + 0.25y = 12.95 (equation 2)
0.20y = 8.20
y = 41
Substituting y = 41 into equation 1:
x + 41 = 95
x = 54
Therefore, there are 54 nickels and 41 quarters in the jar.