calculate the number of grams required to make 100mL of a 4.5M solution of CuSo4 times 5H2O
To calculate the number of grams of CuSO4 times 5H2O required to make 100mL of a 4.5M solution, we need to first calculate the molecular weight of CuSO4 times 5H2O:
Molecular weight of CuSO4 times 5H2O = (63.55 g/mol Cu + 32.06 g/mol S + 4x 16.00 g/mol O + 5x 18.02 g/mol H2O) = 249.69 g/mol
Now, we need to calculate the number of moles of CuSO4 times 5H2O required to make 100mL of a 4.5M solution:
Moles of CuSO4 times 5H2O = Molarity x Volume (in liters) = 4.5 x 0.1/1000 = 0.00045 moles
Finally, we can calculate the mass of CuSO4 times 5H2O required using the formula:
Mass (in grams) = moles x molecular weight = 0.00045 moles x 249.69 g/mol = 0.112 g or 112 mg (rounded to the nearest milligram)
Therefore, 112 mg of CuSO4 times 5H2O is required to make 100mL of a 4.5M solution.