If a two digit number is 18 more than the number formed by reversing the digits.if the sum of digits is 10.find the number
Let the two digits be represented by 10a+b where a and b are digits.
According to the problem, we have:
10a+b = 18 + 10b+a
Simplifying this equation, we get:
9a - 9b = 18
Dividing both sides by 9, we get:
a - b = 2
We also know that the sum of digits is 10, so:
a + b = 10
Solving these two equations simultaneously, we get:
a = 6
b = 4
Therefore, the number is 64.