For the combustion of ethane, beginning with 0.27 mole of CH3 CH3.
how many moles of O₂ are required to completely consume the CH3 CH3?
The balanced chemical equation for the combustion of ethane (CH3CH3) is:
2CH3CH3 + 7O2 -> 4CO2 + 6H2O
This equation tells us that for every 2 moles of ethane, we need 7 moles of oxygen to completely burn the ethane.
Since we have 0.27 mole of ethane, we need to determine how many moles of oxygen are required. We can set up a proportion:
2 mol CH3CH3 / 7 mol O2 = 0.27 mol CH3CH3 / x mol O2
Solving for x, we get:
x = (7 mol O2)(0.27 mol CH3CH3) / 2 mol CH3CH3
x = 0.945 mol O2
Therefore, we need 0.945 moles of O2 to completely consume 0.27 mole of CH3CH3.