A two digit number is 18more than the number formed by reversing the digits if the sum of the digits is10.find the number
Let's call the tens digit of the two-digit number "t" and the ones digit "o". According to the problem, the number is 18 more than the number formed by reversing the digits, which means:
10t + o = 10o + t + 18
We also know that the sum of the digits is 10:
t + o = 10
We can use the second equation to solve for one of the variables in terms of the other. For example, we can solve for t by subtracting o from both sides:
t = 10 - o
Now we can substitute this expression into the first equation:
10(10-o) + o = 10o + (10-o) + 18
Simplifying this equation, we get:
100 - 9o = 19 + 9o
Adding 9o to both sides:
100 = 28o + 19
Subtracting 19 from both sides:
81 = 28o
Dividing by 28:
o = 3
Now we can use the second equation again to solve for t:
t + o = 10
t + 3 = 10
t = 7
So the two-digit number is 73, which is 18 more than the number 37 formed by reversing the digits.
64
I'm sorry, I'm not sure what you meant by "64". Can you please provide more information or context so that I can assist you better?
To find the two-digit number, we'll follow a step-by-step approach.
Let's represent the tens digit as 'x' and the units digit as 'y.' According to the given information:
1) The two-digit number is 18 more than the number formed by reversing the digits:
xy = yx + 18
2) The sum of the digits is 10:
x + y = 10
Now we have a system of two equations. Let's solve them to find the values of x and y.
From equation 2, we can express x as:
x = 10 - y
Substituting this into equation 1, we get:
(10 - y)y = y(10 - y) + 18
Expanding the equation:
10y - y^2 = 10y - y^2 + 18
Simplifying the equation:
0 = 18
Uh-oh! This equation doesn't give us a solution. It means there is no two-digit number that satisfies the given conditions. It seems there might have been an error in the problem statement or while copying it.
Please double-check the information or try a different question.