Declan says that for any number n, the product 4 times n is greater than 4. Which vaule of n shows why Declan is incorrect?
If we take n = 0, then the product 4 times n is 0, which is not greater than 4. Therefore, Declan is incorrect.
Two numbers are graphed on the number line below. Consider the inequality t<r. Which values graphed on the number line make the inequality true?
As per the inequality t < r, we need to find the values of t and r that satisfy this condition.
Looking at the number line, we see that t is to the left of r. Therefore, any combination of values where t is on the left side of r will satisfy the inequality.
For example, if we take t as -5 and r as 2, then we have:
t < r
-5 < 2
This is true since -5 is to the left of 2 on the number line.
Similarly, any other combination of values where t is less than r on the number line will satisfy the inequality t < r.
To show that Declan is incorrect, we need to find a value of 'n' for which the product of 4 times 'n' is not greater than 4.
Let's consider the inequality and simplify it:
4n > 4
Divide both sides of the inequality by 4:
n > 1
This inequality suggests that any value of 'n' greater than 1 will make the product 4 times 'n' greater than 4.
To find a value of 'n' that shows Declan is incorrect, we need to find a value less than or equal to 1.
For instance, let's consider 'n' as 1:
4 × 1 = 4
So, when 'n' is equal to 1, the product of 4 times 'n' is not greater than 4. This means that Declan's claim is incorrect, as there is at least one value of 'n' for which the product is not greater than 4.