A basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. Jameson picks a fruit at random and does not replace it. Then Brittany picks a fruit at random. What is the probability that Jameson gets a banana and Brittany gets a pear?
There are a total of 3+2+2+2+5 = 14 pieces of fruit in the basket.
The probability that Jameson chooses a banana is 2/14 = 1/7.
After Jameson takes a fruit, there are 13 pieces of fruit left, including one pear. Therefore, the probability that Brittany chooses a pear is 1/13.
To find the probability that both events occur, we multiply their probabilities:
(1/7) * (1/13) = 1/91
Therefore, the probability that Jameson picks a banana and Brittany picks a pear is 1/91.