Given the coordinates (3,−2), (11,−2), (3,−4), and (11,−4), what is the length of the base of the quadrilateral, in cm?
The base of the quadrilateral is the line segment connecting the points (3,-2) and (11,-2). This is a horizontal line segment with a length of 11-3=8cm. Therefore, the length of the base of the quadrilateral is 8cm.
You're correct. Any of the four sides could have been considered as the base of the quadrilateral. However, the most common convention is to consider the horizontal side as the base since it makes calculations easier. In this case, the line segment connecting the points (3,-2) and (11,-2) is the base of the quadrilateral and has a length of 8 cm.
The distance between (19,-6) and (8,-6) can be found using the distance formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Where (x1, y1) = (19,-6) and (x2, y2) = (8,-6)
Substituting the values, we get:
d = sqrt((8 - 19)^2 + (-6 - (-6))^2)
= sqrt((-11)^2 + (0)^2)
= sqrt(121)
= 11
Therefore, the distance between (19,-6) and (8,-6) on a coordinate plane is 11 units.
The length of the base of the right triangle can be found by determining the horizontal distance between the two points at the ends of the base.
The coordinates of the two endpoints of the base are (2, 4) and (6, 4). The horizontal distance between these two points is 6 - 2 = 4 units. Therefore, the length of the base of the right triangle is 4 units.
Any of the 4 sides could have been considered the base
What is the distance between (19,−6) and (8,−6) on a coordinate plane?
A right triangle was graphed on a coordinate plane using the coordinates (2, 4), (6, 4), and (6, 10). What is the length of the base of the triangle?
Rectangle ABCD has vertices point A (−5, 1), point B (−2, 1), point C (−2, 6), and point D (−5, 6). Find the perimeter of the rectangle in feet.
Rectangle ABCD has vertices point A (−5, 1), point B (−2, 1), point C (−2, 6), and point D (−5, 6). Find the area of the rectangle in square feet.(1 point)
The area of rectangle ABCD is__square feet.
To find the area of the rectangle, we need to multiply the length and width of the rectangle. We can use either the length of the rectangle AB (which we found in the previous problem to be 7 feet) or the length of the rectangle CD (which is also 7 feet) as the length of the rectangle.
The width of the rectangle is the distance between the y-coordinates of points A and C. The distance between the y-coordinates of these points is 6 - 1 = 5 feet.
Using the length and width, we can find the area of the rectangle:
Area = Length × Width
= 7 × 5
= 35
Therefore, the area of rectangle ABCD is 35 square feet.