You burn 6g of carbon in plenty of air.
C+O2= CO2
a: what volume of gas will form at room temperature
To determine the volume of gas that will form at room temperature, we can use the ideal gas law, which is:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature.
First, we need to find the number of moles of carbon that were burned. The molar mass of carbon (C) is 12.01 g/mol. Since we burned 6 grams of carbon:
moles of carbon (n) = mass / molar mass = 6 g / 12.01 g/mol = 0.5 mol
In the balanced chemical equation, C + O2 → CO2, we can see that 1 mole of carbon reacts with 1 mole of oxygen gas to produce 1 mole of carbon dioxide. Since we had 0.5 moles of carbon, this means that 0.5 moles of carbon dioxide (CO2) will form.
Now, we can use the ideal gas law to determine the volume of the CO2 gas at room temperature (which is normally considered as 298 K or 25°C). The standard pressure for these calculations is usually 1 atmosphere (atm).
We can solve the equation for the volume (V):
V = nRT / P
The ideal gas constant (R) depends on the units we use. Since we're working with atm and L, we'll use the value R = 0.0821 L atm / K mol.
We already determined n = 0.5 mol, and P = 1 atm, and room temperature (T) is 298 K.
Now we can plug in the values into the equation:
V = (0.5 mol)(0.0821 L atm / K mol)(298 K) / 1 atm
V ≈ 12.2 L
So, approximately 12.2 liters of CO2 gas will form at room temperature when 6 grams of carbon are burned.