16 gram of CaC2 and 18 gram of H2O were mixed in the given reaction,
CaC2 + 2H2O it gives C2H2 + Ca(OH)2.
A, what mass of Ca(OH)2 is formed?
CaC2 + 2H2O → C2H2 + Ca(OH)2
16g = 0.25 moles CaC2
18g = 1.0 mole H2O
Since CaC2 is the limiting reactant, you will get 0.25 moles Ca(OH)2
That is 18.5 grams