A triangle has vertices at S(1, 1), T(2, -3), and U(4, 0). The triangle is translated up 3 units. What are the coordinates of the vertices of the image?
To translate the triangle up 3 units, we add 3 to the y-coordinate of each vertex.
The new coordinates of S are (1, 1+3) = (1, 4)
The new coordinates of T are (2, -3+3) = (2, 0)
The new coordinates of U are (4, 0+3) = (4, 3)
Therefore, the vertices of the image are S'(1, 4), T'(2, 0), and U'(4, 3).
To translate a shape up, we add the same value to the y-coordinate of each vertex.
Given that the triangle is translated up 3 units, we add 3 to the y-coordinate of each vertex.
Let's calculate the coordinates of each vertex of the translated triangle:
For vertex S(1, 1):
The new y-coordinate will be 1 + 3 = 4.
So the new coordinates of S will be S'(1, 4).
For vertex T(2, -3):
The new y-coordinate will be -3 + 3 = 0.
So the new coordinates of T will be T'(2, 0).
For vertex U(4, 0):
The new y-coordinate will be 0 + 3 = 3.
So the new coordinates of U will be U'(4, 3).
Therefore, the coordinates of the vertices of the translated triangle are S'(1, 4), T'(2, 0), and U'(4, 3).
To find the coordinates of the image after a translation, we need to add the same constant to the x-coordinates and y-coordinates of each vertex of the original triangle. In this case, we need to translate the triangle up by 3 units, so we will add 3 to the y-coordinates of each vertex.
Let's start with the coordinates of the original triangle:
S(1, 1), T(2, -3), U(4, 0)
To translate the triangle up 3 units, we add 3 to the y-coordinate of each vertex:
S' = (1, 1 + 3) = (1, 4)
T' = (2, -3 + 3) = (2, 0)
U' = (4, 0 + 3) = (4, 3)
Therefore, the coordinates of the image triangle after the translation are:
S'(1, 4), T'(2, 0), U'(4, 3)