Ms. Garcia burns 236 calories riding her bike each hour. She wants to burn more than 354 calories riding her bike at the same rate.

Which inequality represents all possible values for t, the number of hours Ms. Garcia must ride her bike to burn more than 354 calories?

The inequality would be:

236t > 354

Explanation:

We know that Ms. Garcia burns 236 calories each hour riding her bike. So, if she rides for t hours, she will burn 236t calories.

However, we also know that she wants to burn more than 354 calories. Therefore, we set up the inequality:

236t > 354

This inequality states that the number of calories burned (236t) must be greater than 354 in order for Ms. Garcia to achieve her goal.

To solve for t, we divide both sides of the inequality by 236:

t > 354/236

Simplifying, we get:

t > 1.5

So, Ms. Garcia must ride her bike for more than 1.5 hours to burn more than 354 calories.

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The ratio of the number of boys to the number of girls in a choir is 6 to 5. There are 45 girls in the choir. How many boys are in the choir?

A 6161
B 3939
C 5454
D 6

Carolina walked to school on 12 of the 20 school days in March. Which value is NOT equivalent to the fraction of the school days in March that Carolina walked to school?

Responses
A 0.060.06
B 3/53/5
C 60%60%
D 0.60

Carolina walked to school on 12 of the 20 school days in March. Which value is NOT equivalent to the fraction of the school days in March that Carolina walked to school?

Responses
A 0.060.06
B 3/53/5
C 60%60%
D 0.60

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The weights listed in order from least to greatest is:

8 and 1/8, 8.25, 8 and 1/2, 8.625

Therefore, the correct answer is D) 8 and 1/8, 8.25, 8 and 1/2, 8.625.

You're welcome! Feel free to let me know if you have any other questions.

The ratio of boys to girls in the choir is 6 to 5, which can be written as:

boys/girls = 6/5

We are given that there are 45 girls in the choir, so we can use this information to find the number of boys:

boys/45 = 6/5

To solve for the number of boys, we can cross-multiply:

boys = 45 x 6 / 5

boys = 54

Therefore, there are 54 boys in the choir. Answer: 54.