a saturated solution of potassium chloride is prepared and 100.0 G of water at 20° C the solution is heated at 50 Celsius how much more KCI I must be added to obtain the saturated solution?
To determine how much more KCl must be added, we need to know the solubility of KCl at both 20°C and 50°C.
The solubility of KCl in water at 20°C is approximately 34.0 g per 100 g of water, and at 50°C, it is around 45.0 g per 100 g of water.
Next, find the initial mass of KCl that is dissolved in the solution at 20°C:
Initial_mass = (solubility_at_20) x (mass_of_water)
Initial_mass = (34.0 g KCl/ 100 g H2O) x (100 g H2O)
Initial_mass = 34 g KCl dissolved in 100 g H2O at 20°C
Then, determine the maximum mass of KCl that can be dissolved in the 100 g of water at 50°C:
Max_mass = (solubility_at_50) x (mass_of_water)
Max_mass = (45.0 g KCl/ 100 g H2O) x (100 g H2O)
Max_mass = 45 g KCl
Now, subtract the initial mass from the maximum mass to see how much more KCl can be added to saturate the solution at 50°C:
Additional_KCl = Max_mass - Initial_mass
Additional_KCl = 45 g - 34 g
Additional_KCl = 11 g
So, 11 g of KCl must be added to the 100 g of water at 50°C to obtain a saturated solution.