A parabola can be drawn given a focus of (4,−4) and a directrix of x=2. What can be said about the parabola?

Since the directrix is a vertical line of the form x=a, the parabola is vertical and opens either upward or downward. The vertex is halfway between the focus and the directrix, which is at the point (3,-4). The distance from the focus to the vertex is the same as the distance from the vertex to the directrix, which is 1. Therefore, the equation of the parabola is of the form (y-k)^2 = 4p(x-h), where (h,k) is the vertex and p is the distance from the vertex to the focus/directrix. In this case, (h,k) = (3,-4) and p=1, so the equation of the parabola is (y+4)^2 = 4(x-3).