The average age of 10 men is 42,if the average of 6 of them is 45,and the ages of three of them are 29,20 and 35. What is the age of the tenth man
The sum of the ages of the 10 men is 10 * 42 = <<10*42=420>>420.
The sum of the ages of the 6 men is 6 * 45 = <<6*45=270>>270.
So, the sum of the ages of the remaining 4 men is 420 - 270 = <<420-270=150>>150.
The sum of the ages of the three given men is 29 + 20 + 35 = <<29+20+35=84>>84.
So, the age of the tenth man is 150 - 84 = <<150-84=66>>66. Answer: \boxed{66}.