. A force of 10 N causes a spring to extend by 20 mm. Find the extension of the spring when 25 N is applied
We can use Hooke's law to solve this problem:
F = kx
Where F is the applied force, k is the spring constant (which tells us how stiff the spring is), and x is the extension or compression of the spring.
From the given information, we know that:
F1 = 10 N, x1 = 20 mm
F2 = 25 N, x2 = ?
To find the spring constant, we can rearrange Hooke's law:
k = F/x
Using the first set of data, we get:
k = 10 N / 20 mm = 0.5 N/mm
Now we can use this value of k to solve for x2:
x2 = F2/k
x2 = 25 N / 0.5 N/mm = 50 mm
Therefore, the extension of the spring when 25 N is applied is 50 mm.