You roll a number cube twice. Find the probability of an even number, and then find the probability of a number that is NOT 2. Write the probability as a fraction in simplest form.
... can u put the question in less confusing terms???
Could you please rephrase your question in simpler language for me to better understand?
You roll a number cube twice. Find P(even, then not 2). Write the probability as a fraction in simplest form. Explain your answer.
Sure! You roll a regular six-sided dice two times. What's the probability that you'll get an even number on the first roll AND a number that is NOT 2 on the second roll? Write your answer as a fraction in the simplest form.
To find the probability of an event, divide the number of favorable outcomes by the total number of possible outcomes.
1. Probability of getting an even number:
A number cube has six sides, numbered 1 to 6. Out of these, three are even numbers: 2, 4, and 6. So, there are three favorable outcomes (getting an even number) and six possible outcomes (rolling the number cube twice).
Probability of getting an even number = favorable outcomes / total outcomes = 3 / 6 = 1/2
2. Probability of not getting a 2:
There are six possible outcomes (rolling the number cube twice), and one of them is getting a 2. So, the number of favorable outcomes (not getting a 2) would be six minus one, which is five.
Probability of not getting a 2 = favorable outcomes / total outcomes = 5 / 6
Therefore, the probability of not getting a 2 is 5/6.