In the gas phase reaction PC13(g) + C12(g)<==>PC15(g) Kc = 1.9
The system is equilibrium with concentrations [Pc13]=0.5M .what is the PC15 concentration
We can use the equilibrium expression to solve for the concentration of PC15:
Kc = [PC15]/([PC13][Cl2])
1.9 = [PC15]/(0.5 x [Cl2])
We are given the concentration of PC13, but not the concentration of Cl2. However, we can use the fact that the reaction is in equilibrium to determine the concentration of Cl2.
At equilibrium, the amount of PC15 must be equal to the amount of PC13 and Cl2 combined, since the coefficients in the balanced equation are 1, 1, and 1. Therefore:
[PC15] = [PC13] + [Cl2]
Substituting the given concentration of PC13 and solving for [Cl2]:
[Cl2] = [PC15] - [PC13] = x - 0.5
Substituting this expression for [Cl2] into the equilibrium expression:
1.9 = [PC15]/(0.5(x - 0.5))
Solving for x (the concentration of PC15):
x = 1.52 M
Therefore, the concentration of PC15 at equilibrium is 1.52 M.