a 6kg clay ball is thrown directly against a perpendicular brick wall at a velocity of 22m/s and shatters in to three pieces, which all fly backward, as shown in the figure . the wall exerts a force on the ball of 2640N for 0.1sec. ....what is the velocity of the third piece?

First, we need to find the initial momentum of the clay ball. We can do this by multiplying the mass (6kg) by the velocity (22m/s):

Initial momentum = (mass) * (velocity)
Initial momentum = (6kg) * (22m/s)
Initial momentum = 132 kg m/s

Next, we need to find the total impulse the wall exerts on the clay ball. We can do this by multiplying the force (2640N) by the time (0.1s):

Total impulse = (force) * (time)
Total impulse = (2640N) * (0.1s)
Total impulse = 264 kg m/s

Now, we can calculate the final momentum of the clay ball. Since the clay ball shatters into three pieces and they all fly backward, we know that the final momentum will be negative. We can determine the final momentum by subtracting the total impulse from the initial momentum:

Final momentum = (initial momentum) - (total impulse)
Final momentum = (132 kg m/s) - (264 kg m/s)
Final momentum = -132 kg m/s

Since the clay ball shatters into three pieces, we know that the final momentum will be divided among the three pieces. Let's call the velocities of the first, second, and third pieces p1, p2, and p3. Thus:

p1 + p2 + p3 = -132 kg m/s

We are looking for the velocity of the third piece (p3). We don't have enough information to solve the equation with the given information, so we would need more information about the velocities or masses of the individual pieces to solve for p3.

However, if we assume that the masses of the three pieces are equal (which would mean each piece has a mass of 2kg), we could find p3 by assuming equal and opposite velocities for the other two pieces. For example, if p1 = -22 m/s and p2 = 22 m/s, then:

(-22) + (22) + p3 = -132
0 + p3 = -132
p3 = -132 m/s

Although this is a hypothetical example based on assumptions, it demonstrates that more information about the individual pieces is necessary to solve the problem entirely.