Nicholas has a total of twenty-seven nickels and dimes. He has eleven more dimes than nickels. At the mall, Nicholas spent eight nickels and twelve dimes. How much money does he have left?
Let's start by using algebra to solve for the number of nickels (N) and dimes (D) that Nicholas has:
N + D = 27 (equation 1)
D = N + 11 (equation 2)
We can substitute equation 2 into equation 1 to get:
N + (N + 11) = 27
2N + 11 = 27
2N = 16
N = 8
So Nicholas has 8 nickels and 19 dimes.
To find out how much money he has left after spending some of it at the mall, we need to calculate his total amount of money before and after the mall trip.
Before the mall trip, he had:
8 nickels = $0.40
19 dimes = $1.90
Total = $2.30
After the mall trip, he spent:
8 nickels = $0.40
12 dimes = $1.20
Total = $1.60
So he has $2.30 - $1.60 = $0.70 left.