Solve the problem. The surface area of a square pyramid is 116 in.2 and the total area of the pyramid’s four triangular faces is 80 in.2

What is the length of one of the sides? Show your work

Let's use "s" to represent the length of one of the sides of the square base of the pyramid.

We know that the surface area of the pyramid is 116 in.2, so we can write an equation:

s^2 + 4(1/2)*s*l = 116
(Note that the surface area of a pyramid includes the area of its base, which is s^2, and the area of its four triangular faces, which is 4 times the area of one face, which is 1/2 times the base times the height.)

We also know that the total area of the pyramid's four triangular faces is 80 in.2, so we can write another equation:

4(1/2)*s*l = 80

Now we have two equations with two variables (s and l), but we can use the second equation to solve for l in terms of s:

2sl = 80
l = 40/s

We can substitute this expression for l into the first equation:

s^2 + 4(1/2)*s*(40/s) = 116

Simplifying:

s^2 + 80 = 116
s^2 = 36
s = 6

Therefore, the length of one of the sides of the square base of the pyramid is 6 inches.

To solve this problem, we'll use the formula for the surface area of a square pyramid and the given information.

1. Let's start by identifying the variables and values provided:
- Surface area of the square pyramid = 116 in^2
- Total area of the pyramid's four triangular faces = 80 in^2

2. The formula for the surface area of a square pyramid is:
Surface Area = Base Area + 4 × (0.5 × Base Perimeter × Slant Height)

3. In a square pyramid, the base is a square and the slant height is the height of one of the triangular faces.

4. The total area of the four triangular faces (80 in^2) is equal to 4 × (0.5 × Base × Slant Height), since there are four identical triangular faces.

5. We can write the following equation based on the given information:
80 = 4 × (0.5 × Base × Slant Height)

6. Now, let's substitute the value of the surface area (116 in^2) into the surface area formula:
116 = Base Area + 4 × (0.5 × Base Perimeter × Slant Height)

7. Since we have two equations and two variables (Base and Slant Height), we can solve for these variables simultaneously.

8. Let's solve the first equation for Slant Height:
80 = 4 × (0.5 × Base × Slant Height)
80 = 2 × Base × Slant Height
Slant Height = 80 / (2 × Base)
Slant Height = 40 / Base

9. Now, substitute the value of Slant Height in terms of Base into the second equation:
116 = Base Area + 4 × (0.5 × Base Perimeter × (40 / Base))

10. Simplify the equation further:
116 = Base^2 + 4 × (0.5 × 4 × Base × (40 / Base))
116 = Base^2 + 8 × 40
116 = Base^2 + 320

11. Rearrange the equation to isolate Base:
Base^2 = 116 - 320
Base^2 = -204 (This is not possible since we can't have a negative length)

12. Since we can't have a negative length, there must be an error in the given values or the problem itself. Please double-check the values or the wording of the problem.

Without a valid value for the base, it is not possible to determine the length of one of the sides.

To find the length of one side of the square pyramid, we need to use the given information about the surface area and the total area of the four triangular faces.

Let's denote the length of one side of the square base as "x". The area of each triangular face can be calculated by multiplying the base and height, where the base would be equal to the length of one side of the square base, and the height would be the slant height of the pyramid.

The surface area of the square pyramid is given as 116 in^2, so we have:

Surface Area = Area of Base + Area of Four Triangular Faces

116 in^2 = x^2 + 4(Area of Each Triangular Face)

Given that the total area of the four triangular faces is 80 in^2, we can substitute this value into the equation:

116 in^2 = x^2 + 4(80 in^2)
116 in^2 = x^2 + 320 in^2

Now, we can rearrange the equation to isolate the value of x^2:

x^2 = 116 in^2 - 320 in^2
x^2 = -204 in^2

Since the square of a real number cannot be negative, there is no real solution to this equation. Therefore, we cannot determine the length of one side of the square base of the pyramid with the given information.