Write the linear equation 3y=5x−18 in slope-intercept form.(1 point)
The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.
To get the equation 3y = 5x - 18 into slope-intercept form, we need to solve for y.
First, we can divide both sides by 3:
3y/3 = 5x/3 - 18/3
y = (5/3)x - 6
So the slope of this equation is 5/3 and the y-intercept is -6.
Therefore, the slope-intercept form of the equation is:
y = (5/3)x - 6
To write the linear equation 3y = 5x - 18 in slope-intercept form, we need to isolate y on one side of the equation.
First, let's subtract 5x from both sides of the equation:
3y - 5x = -18
Now, to isolate y, divide both sides of the equation by 3:
(3y - 5x) / 3 = -18 / 3
Simplifying, we have:
y - (5/3)x = -6
Finally, we can write the equation in slope-intercept form by rearranging the terms:
y = (5/3)x - 6
Therefore, the linear equation 3y = 5x - 18 in slope-intercept form is y = (5/3)x - 6.
To write the linear equation 3y = 5x - 18 in slope-intercept form, which is in the form y = mx + b, you need to isolate y.
First, divide both sides of the equation by 3:
3y/3 = (5x - 18)/3
This simplifies to:
y = (5/3)x - 6
So, the linear equation 3y = 5x - 18 in slope-intercept form is y = (5/3)x - 6.