What is the force of a 1000 kg truck that is honking and swerving past Mr. Hermans
at 9.8 m/sec2?
This question is not answerable without additional information. The force of the truck would depend on its velocity, acceleration, and the direction of its motion relative to Mr. Hermans. Honking and swerving would not directly affect the force of the truck.
To calculate the force, we need to use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the truck is given as 1000 kg, and the acceleration is given as 9.8 m/sec2.
So, the force (F) can be calculated using the formula:
F = m * a
Plugging in the values:
F = 1000 kg * 9.8 m/sec2
F = 9800 Newtons
Therefore, the force of the truck honking and swerving past Mr. Hermans is 9800 Newtons.
Let me know if I can help you with anything else.
To find the force of the truck, we need to use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
Given:
Mass of the truck (m) = 1000 kg
Acceleration (a) = 9.8 m/s²
Using the formula: force (F) = mass (m) x acceleration (a)
F = 1000 kg x 9.8 m/s²
F = 9800 kg⋅m/s²
Therefore, the force of the truck is 9800 Newtons.