The rate constant of a first order reaction k is 1.00*10^-2/s and an initial concentration of 0.5mol/l. At what time will the concentration reduce to 0.05mol/l
The first order rate law is given by the equation:
ln([A]t/[A]₀) = -kt
Where [A]t is the concentration of the reactant at time t, [A]₀ is the initial concentration of the reactant, k is the rate constant, and t is the time.
Using this equation and the given values, we can solve for t as follows:
ln([A]t/[A]₀) = -kt
ln(0.05/0.5) = -(1.00*10^-2/s) * t
-2.9957 = -0.01t
t = 299.57 seconds
Therefore, the concentration will reduce to 0.05 mol/L after approximately 299.57 seconds, or 5 minutes.