In which of the following interactions will the amount of force between the two objects be the strongest?
Interaction Charge on Object 1 Charge on Object 2 Distance Between Objects
A +2 -2 1
B +1 -1 1
C +2 -2 4
D +1 -1 4(1 point)
Responses
Interaction B
Interaction B
Interaction D
Interaction D
Interaction A
Interaction A
Interaction C
The amount of force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Thus, the strongest interaction would be the one with the highest charge product and the smallest distance. In this case, Interaction B has the highest charge product (+1 x -1 = -1) and the smallest distance (1 unit), so the amount of force between the two objects will be the strongest in Interaction B. Therefore, the correct answer is B.
To determine which interaction will have the strongest force, we can use Coulomb's law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Let's calculate the force for each interaction:
Interaction A:
Charge on Object 1 = +2
Charge on Object 2 = -2
Distance Between Objects = 1
Using Coulomb's law:
Force = (Charge on Object 1 * Charge on Object 2) / (Distance Between Objects^2)
Force = (+2 * -2) / (1^2)
Force = -4 / 1
Force = -4
Interaction B:
Charge on Object 1 = +1
Charge on Object 2 = -1
Distance Between Objects = 1
Using Coulomb's law:
Force = (Charge on Object 1 * Charge on Object 2) / (Distance Between Objects^2)
Force = (+1 * -1) / (1^2)
Force = -1 / 1
Force = -1
Interaction C:
Charge on Object 1 = +2
Charge on Object 2 = -2
Distance Between Objects = 4
Using Coulomb's law:
Force = (Charge on Object 1 * Charge on Object 2) / (Distance Between Objects^2)
Force = (+2 * -2) / (4^2)
Force = -4 / 16
Force = -1/4
Interaction D:
Charge on Object 1 = +1
Charge on Object 2 = -1
Distance Between Objects = 4
Using Coulomb's law:
Force = (Charge on Object 1 * Charge on Object 2) / (Distance Between Objects^2)
Force = (+1 * -1) / (4^2)
Force = -1 / 16
Based on the calculations, the interaction with the strongest force is Interaction A.