How many grams of Ca(OH)2 are contained in 1500ml of 0.0250m Ca(OH)2 solution
To solve this problem, you can use the formula:
moles of Ca(OH)2 = concentration (in moles/L) x volume (in liters)
First, we need to convert the volume from milliliters to liters:
1500 mL = 1500/1000 L = 1.5 L
Next, we can calculate the moles of Ca(OH)2 in the solution:
moles of Ca(OH)2 = 0.0250 mol/L x 1.5 L = 0.0375 mol
Finally, we can convert the moles of Ca(OH)2 to grams:
mass of Ca(OH)2 = moles x molar mass
The molar mass of Ca(OH)2 is 74.09 g/mol (1 calcium atom at 40.08 g/mol, 2 oxygen atoms at 16.00 g/mol each, and 2 hydrogen atoms at 1.01 g/mol each).
mass of Ca(OH)2 = 0.0375 mol x 74.09 g/mol = 2.78 g
Therefore, there are 2.78 grams of Ca(OH)2 in 1500 mL of 0.0250 M Ca(OH)2 solution.