Amelia thinks of a whole number.
When she divides her number by 4, the result has 1 decimal place and is greater than 7 but less than 8.
What is Amelia's original number?
Let's call Amelia's original number "x".
From the problem, we know that when x is divided by 4, the result has 1 decimal place and is between 7 and 8. This can be written as:
7 < x/4 < 8
We can solve for x by multiplying all sides of the inequality by 4:
28 < x < 32
So Amelia's original number could be any whole number between 28 and 32, inclusive.
To find Amelia's original number, we need to solve the following equation:
x/4 = 7.1, where x represents the original number.
To isolate x, we can multiply both sides of the equation by 4:
x = 7.1 * 4
Calculating the right side of the equation:
x = 28.4
Therefore, Amelia's original number is 28.4.
To find Amelia's original number, we need to look for a whole number that, when divided by 4, gives a result with 1 decimal place and falls between 7 and 8.
Let's start by considering the range between 7 and 8. We know Amelia's number is greater than 7 but less than 8, which means it could be any number between these two values, exclusive.
Next, we need to find a whole number that, when divided by 4, gives a result with 1 decimal place. This means the resulting quotient will have the form x.y, where x is a whole number, and y is a single decimal digit.
Now, we can try different whole numbers within the given range and check if they meet the conditions. Let's check each number to find the one that satisfies all the given conditions.
Starting with the number 8:
8 ÷ 4 = 2
The result is not in the form x.y, so let's try the next number:
7 ÷ 4 = 1.75
Here, we have a result in the form x.y, and it falls within the given range (greater than 7 but less than 8).
Therefore, Amelia's original number is 7.
To solve this type of problem, you need to consider the given conditions and test different numbers until you find one that satisfies all the requirements.