Two similar waves are traveling through the same medium. Wave A has a frequency that is 3 times that of wave B.
How do their wavelengths compare?
Which of the following is the best answer?
A) λA=19λB
lambda sub cap A is equal to 1 ninth lambda sub cap b
B) λA=3λB
lambda sub cap A is equal to 3 lambda sub cap b
C) λA=13λB
lambda sub cap A is equal to 1 third lambda sub cap b
D) λA=λB
lambda sub cap A is equal to lambda sub cap b
B) λA=3λB.
The wavelength is directly proportional to the frequency. Since wave A has a frequency that is three times greater than wave B, its wavelength will also be three times greater. Therefore, λA=3λB.