what are the first 4 terms when using this equation? n(n-2)-3
The first 4 terms of the given equation n(n-2)-3 can be found by substituting the values of n equal to 1, 2, 3, and 4 respectively, as follows:
For n = 1,
n(n-2)-3 = 1(1-2)-3 = -4
For n = 2,
n(n-2)-3 = 2(2-2)-3 = -3
For n = 3,
n(n-2)-3 = 3(3-2)-3 = 0
For n = 4,
n(n-2)-3 = 4(4-2)-3 = 5
Therefore, the first 4 terms when using the given equation are: -4, -3, 0, and 5.