what is the area of the figure below
the figure below is a trapizoid
5in 3in 12in
a 18in^2
b30in^2
c36in^2
d60in^2
To find the area of a trapezoid, you use the formula:
Area = [(sum of the bases) / 2] x height
In this case, the bases are 5in and 12in, and the height is 3in.
So, plugging in those values:
Area = [(5+12) / 2] x 3
Area = (17 / 2) x 3
Area = 25.5
Therefore, the area of the trapezoid is approximately 25.5 square inches, which would be closest to option B: 30in^2.
su
To find the area of a trapezoid, you can use the formula:
Area = (1/2) * (base1 + base2) * height
In this case, the bases are 5 inches and 12 inches, and the height is 3 inches. Plugging these values into the formula, we get:
Area = (1/2) * (5 + 12) * 3
Area = (1/2) * 17 * 3
Area = (1/2) * 51
Area = 25.5 square inches
So, the area of the trapezoid is 25.5in^2.
To find the area of a trapezoid, you can use the formula:
Area = (1/2) × (a + b) × h
where:
a and b are the lengths of the parallel sides of the trapezoid
h is the height (or perpendicular distance) between the parallel sides
In the given trapezoid, you have the following measurements:
a = 5 inches (length of one parallel side)
b = 12 inches (length of the other parallel side)
h = 3 inches (height)
Now, plug these values into the formula to calculate the area:
Area = (1/2) × (5 + 12) × 3
= (1/2) × 17 × 3
= (1/2) × 51
= 25.5 in^2
Therefore, the area of the trapezoid is approximately 25.5 square inches.
However, none of the options provided match this calculation exactly. I suspect there might be an error either in the given figure or the provided answer choices. I recommend double-checking the measurements and answer options.