How many GRAMS of carbon monoxide are present in 1.92 moles of this compound?
The molar mass of carbon monoxide (CO) is approximately 28 g/mol. To find the mass of 1.92 moles of CO, we can use the following conversion:
1.92 moles CO x 28 g CO/1 mole CO = 53.76 g CO
Therefore, there are 53.76 grams of carbon monoxide present in 1.92 moles of this compound.
To determine the number of grams of carbon monoxide in 1.92 moles, we need to use the molar mass of carbon monoxide (CO). The molar mass of carbon is 12.01 grams/mole, and the molar mass of oxygen is 16.00 grams/mole.
To find the molar mass of carbon monoxide, we add the molar masses of carbon and oxygen:
Molar mass of CO = (1 × molar mass of C) + (1 × molar mass of O)
= (1 × 12.01 g/mol) + (1 × 16.00 g/mol)
= 12.01 g/mol + 16.00 g/mol
= 28.01 g/mol
Now we can calculate the grams of carbon monoxide:
Grams of CO = Moles of CO × Molar mass of CO
= 1.92 moles × 28.01 g/mol
= 53.8272 grams
Therefore, there are approximately 53.83 grams of carbon monoxide in 1.92 moles of the compound.