A bag contains 6 green marbles and 5 white marbles. You select a marble at random. What are the odds in favor of picking a green marble?
A. 1:6
B. 5:6
C. 6:5
D. 6:11
The probability of picking a green marble can be found by dividing the number of green marbles by the total number of marbles:
P(green) = 6/11
The odds in favor of picking a green marble can be expressed as the ratio of the number of green marbles to the number of non-green marbles:
Odds in favor of green = 6 : 5
Therefore, the answer is option D: 6:11.
WRONG!
The bot found probability, not odds
prob(green) = 6/11
prob(not green) = 5/11
odds in favour of green = 6/11 : 5/11 = 6 : 5
To determine the odds in favor of picking a green marble, we need to find the ratio of favorable outcomes to total outcomes.
In this case, the number of green marbles is 6, which is the number of favorable outcomes. The total number of marbles is 6 (green marbles) + 5 (white marbles) = 11, which is the total number of outcomes.
Therefore, the odds in favor of picking a green marble are 6:11, which corresponds to option D.
To find the odds in favor of picking a green marble, we need to determine the number of green marbles relative to the total number of marbles.
In this case, there are 6 green marbles and 5 white marbles, making a total of 11 marbles.
So the odds in favor of picking a green marble can be calculated as the number of green marbles divided by the total number of marbles:
Odds in favor of picking a green marble = number of green marbles / total number of marbles
= 6 / 11
Therefore, the odds in favor of picking a green marble are 6:11.
The correct answer is option D.