A number cube with the numbers 1 through 6 is rolled. Find the given probability.
P(number < 2)
A. start fraction 1 over 6 end fraction
B. start fraction 2 over 6 end fraction
C. The fraction is four-sixths.
D. three-sixths
The only number which is less than 2 on the number cube is 1. Since there are 6 equally likely outcomes when rolling the number cube, the probability of rolling a number less than 2 is the probability of rolling a 1, which is 1/6.
So the answer is A. start fraction 1 over 6 end fraction.
To find the probability of an event, you need to find the number of favorable outcomes and divide it by the total number of possible outcomes.
In this case, the event is "number < 2," which means rolling a number less than 2 on the number cube. There is only one favorable outcome, which is rolling a 1.
The total number of possible outcomes is 6, because there are 6 numbers on the number cube (1, 2, 3, 4, 5, and 6).
So, the probability of rolling a number less than 2 is 1/6.
Therefore, the answer is option A: start fraction 1 over 6 end fraction.
To find the probability that the number rolled is less than 2, we need to determine the number of favorable outcomes (numbers less than 2) and divide it by the total number of possible outcomes (numbers 1 through 6).
The favorable outcomes are the numbers 1, since it is the only number less than 2. The total number of possible outcomes is 6, as there are 6 numbers on the cube (1, 2, 3, 4, 5, 6).
So, the probability is P(number < 2) = favorable outcomes / total outcomes = 1/6.
Therefore, the correct choice is A. P(number < 2) = start fraction 1 over 6 end fraction.