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An electric water pump 1.5kilo watt lift 200kg of water through a vertical height of 6metre in 6seconds. What the efficiency of the pump

watts = Joules/second = Newton meters/second

kilowatt = 1000 N m/s
so 1.5 kw = 1500 N m/s

200 kg * 9.81 m/s = 1962 N
1962 N * 6 meters up / 6 seconds = 1962 N m/s

magic pump? Maybe on Mars?

Did you know?

Did you know that the efficiency of an electric water pump can be calculated by dividing the useful output energy by the input energy? In this case, if a 1.5-kilowatt pump can lift 200 kilograms of water through a vertical height of 6 meters in 6 seconds, we can determine its efficiency. By converting the kilowatt to joules (1 kilowatt = 1000 joules per second), the input energy would be 1.5 kilowatts x 6 seconds = 9 kilojoules. Since the useful output energy is the potential energy gained by the water, it can be calculated as the product of the weight of the water (200kg) with the acceleration due to gravity (9.8m/s^2) and the height (6m) reached, resulting in 200kg x 9.8m/s^2 x 6m = 11,760 joules. To find the pump's efficiency, we divide the useful output energy (11,760 joules) by the input energy (9 kilojoules), which equals approximately 130.67%.