The wavelengths of visible light vary from about 300 nm to 700 nm. What is the range of frequencies of visible light in a vacuum?(1 point)
Responses
a) 9⋅10¹⁰ Hz to 2.1⋅10¹¹ Hz
9⋅10¹⁰ Hz to 2.1⋅10¹¹ Hz
b) 4.28⋅10⁵ Hz to 1⋅10⁶ Hz
4.28⋅10⁵ Hz to 1⋅10⁶ Hz
c) 4.29⋅10¹⁴ Hz to 1⋅10¹⁵ Hz
4.29⋅10¹⁴ Hz to 1⋅10¹⁵ Hz
d) 90 Hz to 210 Hz
c) 4.29⋅10¹⁴ Hz to 1⋅10¹⁵ Hz.
The frequency of visible light can be calculated using the formula:
frequency = speed of light / wavelength
In a vacuum, the speed of light is constant at 3.00 x 10^8 m/s. Converting the given wavelength range from nm to m:
300 nm = 3.00 x 10^-7 m
700 nm = 7.00 x 10^-7 m
Using the formula above:
frequency (min) = 3.00 x 10^8 m/s / 7.00 x 10^-7 m = 4.29 x 10^14 Hz
frequency (max) = 3.00 x 10^8 m/s / 3.00 x 10^-7 m = 1.00 x 10^15 Hz
Therefore, the range of frequencies of visible light in a vacuum is 4.29 x 10^14 Hz to 1.00 x 10^15 Hz.
c) 4.29⋅10¹⁴ Hz to 1⋅10¹⁵ Hz
The wavelengths of visible light range from about 300 nm to 700 nm. To find the range of frequencies, we can use the relationship between wavelength and frequency, which is given by the equation:
c = λν
Where:
c = the speed of light in a vacuum (approximately 3 x 10^8 m/s)
λ = wavelength
ν = frequency
Rearranging the equation, we can solve for the frequency (ν):
ν = c / λ
Substituting the given wavelength range, we get:
ν = (3 x 10^8 m/s) / (300 x 10^-9 m) = 1 x 10^15 Hz (approx.)
ν = (3 x 10^8 m/s) / (700 x 10^-9 m) = 4.29 x 10^14 Hz (approx.)
Therefore, the range of frequencies of visible light in a vacuum is approximately 4.29 x 10^14 Hz to 1 x 10^15 Hz.
The correct answer is:
c) 4.29⋅10¹⁴ Hz to 1⋅10¹⁵ Hz
To find the range of frequencies of visible light in a vacuum, we can use the equation:
c = λν
Where:
- c is the speed of light in a vacuum (approximately 3.0 x 10^8 m/s)
- λ is the wavelength of light
- ν is the frequency of light
Rearranging the equation, we get:
ν = c / λ
Now, let's calculate the frequencies at the two extreme ends of the range:
For the lower end of the range (wavelength = 300 nm or 3.0 x 10^-7 m):
ν = (3.0 x 10^8 m/s) / (3.0 x 10^-7 m)
ν ≈ 1.0 x 10^15 Hz
For the upper end of the range (wavelength = 700 nm or 7.0 x 10^-7 m):
ν = (3.0 x 10^8 m/s) / (7.0 x 10^-7 m)
ν ≈ 4.29 x 10^14 Hz
Therefore, the range of frequencies of visible light in a vacuum is approximately 4.29 x 10^14 Hz to 1.0 x 10^15 Hz.
So the correct answer is:
c) 4.29 x 10^14 Hz to 1.0 x 10^15 Hz