The roots of the equation are 14 and 2.
What is the quadratic equation?
［A 22-16x+28=0
【Br' +128-16=0
[C] x2-16x-28=0
[DIx+28x-12=0
To find the quadratic equation with roots 14 and 2, we can use the fact that if r and s are the roots of a quadratic equation ax^2 + bx + c = 0, then the equation can be written as a(x - r)(x - s) = 0.
So, if the roots are 14 and 2, then the quadratic equation can be written as a(x - 14)(x - 2) = 0.
Expanding this equation, we get:
a(x^2 - 16x + 28) = 0
So, the quadratic equation is x^2 - 16x + 28 = 0. Answer choice C is correct.