A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.
a) find BC, the distance from Tower 2 to the plane, to the nearest foot.
b) find CD, the height of the plane from the ground, to the nearest foot.
If CD=h and BC=x, then
h/x = tan24°
h/(x+7600) = tan16°
or,
h = 0.4452x
h = 0.2867x + 2179.2649
0.4452x = 0.2867x + 2179.2649
BC = x = 13750
CD = h = 6121