A ball attached to a string is whirled at a constant speed of 2.0 meters per second in a horizontal circle and has a radius of 0.50 meters.
What is the magnitude of the ball's centripetal acceleration, in m/s2?
The centripetal acceleration of an object moving in a circle is given by the formula:
a = v^2 / r
where a is the centripetal acceleration, v is the speed of the object, and r is the radius of the circle.
In this case, the ball is whirled at a constant speed of 2.0 meters per second in a circle with a radius of 0.50 meters. Therefore, the magnitude of the ball's centripetal acceleration is:
a = (2.0 m/s)^2 / 0.50 m
a = 8.0 m/s^2
So the magnitude of the ball's centripetal acceleration is 8.0 m/s^2.