Larry is building a frame around a rectangular picture. He will need 44 inches of wood to do the entire frame. If the frame is 12 inches long, how wide is the frame?
Let's assume that the width of the frame is x inches.
The perimeter of the rectangular picture with the frame is the sum of the lengths of all four sides.
Perimeter = 2(length + width)
The length of the rectangular picture is given as 12 inches.
So, the perimeter of the picture with the frame is:
44 inches = 2(12 + x + 12 + x)
44 inches = 2(24 + 2x)
44 inches = 48 + 4x
Subtracting 48 from both sides:
44 - 48 inches = 4x
-4 inches = 4x
Dividing both sides by 4:
x = -1
Since the width of the frame cannot be negative, this means that there is no solution to this problem.
Therefore, the question is not possible to solve.